Two Sum II - Input array is sorted

Two Sum II - Input array is sorted:

Problem Description:

Given an array of integers that is already sorted in ascending order, find two numbers such that they add up to a specific target number.

The function twoSum should return indices of the two numbers such that they add up to the target, where index1 must be less than index2.


Note:

Your returned answers (both index1 and index2) are not zero-based.

You may assume that each input would have exactly one solution and you may not use the same element twice.

 


Example 1:

Input: numbers = [2,7,11,15], target = 9

Output: [1,2]

Explanation: The sum of 2 and 7 is 9. Therefore index1 = 1, index2 = 2.


Example 2:

Input: numbers = [2,3,4], target = 6

Output: [1,3]


Example 3:

Input: numbers = [-1,0], target = -1

Output: [1,2]

 


Constraints:

2 <= nums.length <= 3 * 104

-1000 <= nums[i] <= 1000

nums is sorted in increasing order.

-1000 <= target <= 1000


Program:

class Solution {

    public int[] twoSum(int[] nums, int target) {

        int l = 0;

        int r = nums.length-1;

        while(l<r)

        {

             if(nums[l]+nums[r] == target)

             {

                 return new int[] {l+1, r+1};

             }

            else if(nums[l]+nums[r] > target)

            {

                r-=1;

            }

            else

            {

                l+=1;

            }

        }

        return new int[0] ;

    }

}


Execution: 

Successfully Executed👍



Reference 👉 Two Sum II - Input array is sorted


  Happy Coding💻:-)


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